A projectile was thrown with 45 degree from the ground at a velocity of 44.3 ms−1 44.3 \mathrm{~ms}^{-1} . Calculate the vertical position (with one decimal place) of the projectile at a horizontal distance of 100 m .

Question

A projectile was thrown with 45 degree from the ground at a velocity of 44.3 ms−1 44.3 \mathrm{~ms}^{-1} . Calculate the vertical position (with one decimal place) of the projectile at a horizontal distance of 100 m .

Accepted Answer

খ. 50.0 m

ব্যাখ্যা: প্রাসটির গতিপথের সমীকরণ: $y = x 	an	heta - \frac{g x^2}{2 v_0^2 \cos^2	heta}$। এখানে $	heta = 45^\circ$, $v_0 = 44.3	ext{ ms}^{-1}$, $x = 100	ext{ m}$ এবং $g = 9.81	ext{ ms}^{-2}$ ধরলে, $2 v_0^2 \cos^2(45^\circ) = v_0^2 = (44.3)^2 \approx 1962.5$। অতএব, $y = 100(1) - \frac{9.81 	imes 100^2}{1962.5} \approx 100 - 49.99 = 50.01	ext{ m} \approx 50.0	ext{ m}$।

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