Consider a cell consisting of Zn(s)|Zn2+ (1.00×10-5 M)|| Ag+(0.10M)|Ag(s) and standard reduction potentials of the cell are E°Zn(red)=-0.76V and E°Ag(red)=0.80V at 25°C. For this cell the following parameters age givenThe cell reaction isi. Zn(s)+2Ag+(aq)= Zn2+(aq)+2Ag(s)ii.Ecell=1.6488Viii.ΔG°=-3.01×105JWhich of the following is more appropriate?

Question

Consider a cell consisting of Zn(s)|Zn2+ (1.00×10-5 M)|| Ag+(0.10M)|Ag(s) and standard reduction potentials of the cell are E°Zn(red)=-0.76V and E°Ag(red)=0.80V at 25°C. For this cell the following parameters age givenThe cell reaction isi. Zn(s)+2Ag+(aq)=> Zn2+(aq)+2Ag(s)ii.Ecell=1.6488Viii.ΔG°=-3.01×105JWhich of the following is more appropriate?

Accepted Answer

ঘ. i, ii & iii

ব্যাখ্যা: i. কোষ বিক্রিয়া: অ্যানোড জারণ $	ext{Zn} ightarrow 	ext{Zn}^{2+} + 2e^-$ এবং ক্যাথোড বিজারণ $2	ext{Ag}^+ + 2e^- ightarrow 2	ext{Ag}$। সুতরাং মোট কোষ বিক্রিয়া: $	ext{Zn(s)} + 2	ext{Ag}^+(	ext{aq}) ightarrow 	ext{Zn}^{2+}(	ext{aq}) + 2	ext{Ag(s)}$ (সঠিক)।
ii. $E^\circ_{	ext{cell}} = E^\circ_{	ext{Ag}^+/	ext{Ag}} - E^\circ_{	ext{Zn}^{2+}/	ext{Zn}} = 0.80 - (-0.76) = 1.56	ext{ V}$।
নার্নস্ট সমীকরণানুসারে:
$E_{	ext{cell}} = E^\circ_{	ext{cell}} - \frac{0.0592}{2} \log\frac{[	ext{Zn}^{2+}]}{[	ext{Ag}^+]^2} = 1.56 - 0.0296 \log\frac{10^{-5}}{(0.1)^2} = 1.56 - 0.0296(-3) = 1.56 + 0.0888 = 1.6488	ext{ V}$ (সঠিক)।
iii. $\Delta G^\circ = -nFE^\circ_{	ext{cell}} = -2 	imes 96500 	imes 1.56 = -3.01 	imes 10^5	ext{ J}$ (সঠিক)।
অতএব তিনটি বিবৃতিই সঠিক।

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