Interference fringes are produced on a screen at a distance of 1.50 m from two slits having separation of 0.6×10−3 0.6 imes 10^{-3} . If the width of interference fringe is 1.5×10−3 1.5 imes 10^{-3} , determine the wavelength of light.

Question

Interference fringes are produced on a screen at a distance of 1.50 m from two slits having separation of 0.6×10−3 0.6 	imes 10^{-3} . If the width of interference fringe is 1.5×10−3 1.5 	imes 10^{-3} , determine the wavelength of light.

Accepted Answer

গ. 6000A˚ 	ext{\AA}

ব্যাখ্যা: ডোরা প্রস্থ (fringe width) $\beta = \frac{\lambda D}{d}$। এখানে, $D = 1.50	ext{ m}$, $d = 0.6 	imes 10^{-3}	ext{ m}$, এবং $\beta = 1.5 	imes 10^{-3}	ext{ m}$। সুতরাং, আলোর তরঙ্গদৈর্ঘ্য $\lambda = \frac{\beta d}{D} = \frac{1.5 	imes 10^{-3} 	imes 0.6 	imes 10^{-3}}{1.50} = 6 	imes 10^{-7}	ext{ m} = 6000	ext{ \AA}$।

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