Bangladesh uses 1.2×1017 J 1.2 imes 10^{17} \mathrm{~J} of electrical energy per year.If all this energy came from the fission of 235U { }^{235} \mathrm{U} at Ruppur nuclear power plant which releases 200MeV 200 \mathrm{MeV} per fission event .How many killogramof 235U { }^{235} \mathrm{U} would be used per year?(1amu=1.6605∗10−27 kg) \left(1 \mathrm{amu}=1.6605 * 10^{-27} \mathrm{~kg} ight)

Question

Bangladesh uses 1.2×1017 J 1.2 	imes 10^{17} \mathrm{~J} of electrical energy per year.If all this energy came from the fission of 235U { }^{235} \mathrm{U} at Ruppur nuclear power plant which releases 200MeV 200 \mathrm{MeV} per fission event .How many killogramof 235U { }^{235} \mathrm{U} would be used per year?(1amu=1.6605∗10−27 kg) \left(1 \mathrm{amu}=1.6605 * 10^{-27} \mathrm{~kg}ight)

Accepted Answer

ক. 1463.87kg

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