AI-তৈরি নমুনা উত্তর ভুল গড় হতে ∑ x = 20 × 15 = 300 \sum x = 20 \times 15 = 300 ∑ x = 20 × 15 = 300 ।
ভুল ভেদাঙ্ক = 3 2 = 9 = 3^2 = 9 = 3 2 = 9 , সুতরাং ∑ x 2 20 − 15 2 = 9 ⇒ ∑ x 2 = 20 × 234 = 4680 \frac{\sum x^2}{20} - 15^2 = 9 \Rightarrow \sum x^2 = 20 \times 234 = 4680 20 ∑ x 2 − 1 5 2 = 9 ⇒ ∑ x 2 = 20 × 234 = 4680 ।
সঠিক ∑ x = 300 − ( 28 + 12 ) + ( 20 + 22 ) = 300 − 40 + 42 = 302 \sum x = 300 - (28 + 12) + (20 + 22) = 300 - 40 + 42 = 302 ∑ x = 300 − ( 28 + 12 ) + ( 20 + 22 ) = 300 − 40 + 42 = 302 । সঠিক গড় = 302 20 = 15.1 = \frac{302}{20} = 15.1 = 20 302 = 15.1 ।
সঠিক ∑ x 2 = 4680 − ( 28 2 + 12 2 ) + ( 20 2 + 22 2 ) = 4680 − ( 784 + 144 ) + ( 400 + 484 ) = 4680 − 928 + 884 = 4636 \sum x^2 = 4680 - (28^2 + 12^2) + (20^2 + 22^2) = 4680 - (784 + 144) + (400 + 484) = 4680 - 928 + 884 = 4636 ∑ x 2 = 4680 − ( 2 8 2 + 1 2 2 ) + ( 2 0 2 + 2 2 2 ) = 4680 − ( 784 + 144 ) + ( 400 + 484 ) = 4680 − 928 + 884 = 4636 ।
সঠিক ভেদাঙ্ক = 4636 20 − ( 15.1 ) 2 = 231.8 − 228.01 = 3.79 = \frac{4636}{20} - (15.1)^2 = 231.8 - 228.01 = 3.79 = 20 4636 − ( 15.1 ) 2 = 231.8 − 228.01 = 3.79 ।
সঠিক পরিমিত ব্যবধান = 3.79 = 1.95 = \sqrt{3.79} = 1.95 = 3.79 = 1.95 (প্রায়)। উত্তর: গড় 15.1 15.1 15.1 এবং পরিমিত ব্যবধান প্রায় 1.95 1.95 1.95 ।