A body is projected with a velocity of 100 m/sec 100 ext{ m/sec} at an angle of 30 30 degree with the horizon (g=9.8 m/sec2) (g = 9.8 ext{ m/sec}^2) . The maximum height of the projectile is-

Question

A body is projected with a velocity of 100 m/sec 100 	ext{ m/sec} at an angle of 30 30 degree with the horizon (g=9.8 m/sec2) (g = 9.8 	ext{ m/sec}^2) . The maximum height of the projectile is-

Accepted Answer

খ. 127.55 m

ব্যাখ্যা: প্রাসটির সর্বোচ্চ উচ্চতা $H = \frac{v_0^2 \sin^2	heta}{2g}$। এখানে $v_0 = 100	ext{ m/s}$, $	heta = 30^\circ$ এবং $g = 9.8	ext{ m/s}^2$। মান বসিয়ে পাই, $H = \frac{100^2 	imes \sin^2(30^\circ)}{2 	imes 9.8} = \frac{10000 	imes 0.25}{19.6} \approx 127.55	ext{ m}$।

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