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From the given Carnot cycle, the process from point A to B is an isothermal expansion.

Given data:

• Number of moles, $n = 3\text{ mol}$
• Temperature at stage AB, $T_1 = 30^\circ\text{C} = (30 + 273.15)\text{ K} = 303.15\text{ K}$
• Expansion ratio, $\frac{V_2}{V_1} = 2$
• Universal gas constant, $R = 8.314\text{ J}/(\text{mol}\cdot\text{K})$

The work done during isothermal expansion from point A to B is given by:
$W_{AB} = n R T_1 \ln\left(\frac{V_2}{V_1}\right)$

Substituting the values:
$W_{AB} = 3 \times 8.314 \times 303.15 \times \ln(2)$
$W_{AB} = 7560.56 \times 0.69315 \approx 5240.6 \text{ J} \text{ (or } 5238.45\text{ J)}$

Answer: The work done from point A to B is approximately $5238.5\text{ J}$ (or $5.24\text{ kJ}$).