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From the given graph:
Temperature at point A, $T_A = 300\text{ K}$
Temperature at point B, $T_B = 400\text{ K}$
Number of moles, $n = 1\text{ mol}$

For 1 mole of an ideal gas, the kinetic energy is given by:
$E_k = \frac{3}{2}RT$

Therefore, the difference in kinetic energy between points A and B is:
$\Delta E_k = \frac{3}{2}R(T_B - T_A)$
$\Delta E_k = \frac{3}{2} \times 8.314\text{ J}\cdot\text{mol}^{-1}\cdot\text{K}^{-1} \times (400\text{ K} - 300\text{ K})$
$\Delta E_k = 1.5 \times 8.314 \times 100\text{ J} = 1247.1\text{ J}$

Answer: $1247.1\text{ J}$