If the hydrogen ion concentration of a fruit juice is 3.3×10-2 M ,What is the pH?

Question

Accepted Answer

ঘ. 1.48

ব্যাখ্যা: $	ext{pH} = -\log_{10}[	ext{H}^+]$
দেওয়া আছে, $[	ext{H}^+] = 3.3 	imes 10^{-2}	ext{ M}$

$	ext{pH} = -\log_{10}(3.3 	imes 10^{-2}) = 2 - \log_{10}(3.3) \approx 2 - 0.5185 = 1.4815 \approx 1.48$।

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