পদার্থবিজ্ঞান প্রশ্ন

AI-তৈরি নমুনা উত্তর

Given data:
Mass of the object, $m = 25\text{ kg}$
Length of the ladder, $L = 20\text{ m}$
Angle with the wall, $\theta = 30^\circ$
Total work done, $W = 9800\text{ J}$
Acceleration due to gravity, $g = 9.8\text{ m/s}^2$

The vertical height gained is:
$h = L \cos 30^\circ = 20 \times \frac{\sqrt{3}}{2} = 10\sqrt{3}\text{ m} \approx 17.32\text{ m}$

Total work done by the person in lifting himself and the object against gravity is:
$W = (W_{\text{person}} + W_{\text{object}}) \times h$
$9800 = (W_{\text{person}} + m g) \times 10\sqrt{3}$
$W_{\text{person}} + (25 \times 9.8) = \frac{9800}{10\sqrt{3}}$
$W_{\text{person}} + 245 = 565.803$
$W_{\text{person}} = 565.803 - 245 = 320.80\text{ N}$

Therefore, the weight of the person is approximately 320.8 N (or mass $\approx 32.73\text{ kg}$).