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AI-তৈরি নমুনা উত্তর

Let the total height from which the object is dropped be $H = 60\text{ m}$.
Let the height from the ground where the kinetic energy is three times the potential energy be $h$.

At height $h$ from the ground:

• Potential energy, $E_p = mgh$
• Distance fallen by the object, $x = H - h$
• Kinetic energy, $E_k = mg(H - h)$

According to the question:
$E_k = 3 E_p$
$mg(H - h) = 3mgh$
$H - h = 3h$
$4h = H$
$h = \frac{H}{4} = \frac{60}{4} = 15\text{ m}$

Therefore, at a height of 15 m from the ground, the kinetic energy will be three times the potential energy.