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Given data:
Length, $l = 10\text{ m}$
Width, $w = 5\text{ m}$
Depth, $d = 10\text{ m}$
Volume of water, $V = 10 \times 5 \times 10 = 500\text{ m}^3$
Mass of water, $m = V \times \rho = 500 \times 1000 = 5 \times 10^5\text{ kg}$
Displacement of the center of mass, $h = \frac{d}{2} = \frac{10}{2} = 5\text{ m}$
Acceleration due to gravity, $g = 980\text{ cm s}^{-2} = 9.8\text{ m s}^{-2}$
Time, $t = 30\text{ minutes} = 30 \times 60 = 1800\text{ s}$

Work done to empty the pond:
$W = mgh = (5 \times 10^5\text{ kg}) \times 9.8\text{ m/s}^2 \times 5\text{ m} = 2.45 \times 10^7\text{ J}$

Power of the pump:
$P = \frac{W}{t} = \frac{2.45 \times 10^7}{1800} \approx 13611.11\text{ W}$

In horsepower:
$P = \frac{13611.11}{746} \approx 18.25\text{ HP}$

Answer: 18.25 HP