tan⁡x+tan⁡3x+tan⁡4x=tan⁡xtan⁡3xtan⁡4x হলে, x=? \begin{array}{l} an x+ an 3 x+ an 4 x= an x an 3 x an 4 x ext { হলে, } x=? \end{array}

Question

tan⁡x+tan⁡3x+tan⁡4x=tan⁡xtan⁡3xtan⁡4x হলে, x=? \begin{array}{l} 	an x+	an 3 x+	an 4 x=	an x 	an 3 x 	an 4 x 	ext { হলে, } x=? \end{array}

Accepted Answer

ঘ. nπ4 \frac{n \pi}{4}

ব্যাখ্যা: প্রদত্ত সমীকরণ: $	an x + 	an 3x + 	an 4x = 	an x 	an 3x 	an 4x \implies 	an x + 	an 3x = -	an 4x(1 - 	an x 	an 3x) \implies \frac{	an x + 	an 3x}{1 - 	an x 	an 3x} = -	an 4x \implies 	an(4x) = -	an 4x \implies 2	an 4x = 0 \implies 	an 4x = 0 \implies 4x = n\pi \implies x = \frac{n\pi}{4}$।

গণিত প্রশ্ন

সম্পর্কিত প্রশ্ন