AI-তৈরি নমুনা উত্তর
ধরি,
I = ∫ d x cos x + sin x I = \int \frac{dx}{\cos x + \sin x} I = ∫ c o s x + s i n x d x
লব ও হরকে 1 2 \frac{1}{\sqrt{2}} 2 1 দ্বারা গুণ করে পাই,
I = 1 2 ∫ d x 1 2 cos x + 1 2 sin x I = \frac{1}{\sqrt{2}} \int \frac{dx}{\frac{1}{\sqrt{2}}\cos x + \frac{1}{\sqrt{2}}\sin x} I = 2 1 ∫ 2 1 c o s x + 2 1 s i n x d x
= 1 2 ∫ d x cos x cos π 4 + sin x sin π 4 = \frac{1}{\sqrt{2}} \int \frac{dx}{\cos x \cos\frac{\pi}{4} + \sin x \sin\frac{\pi}{4}} = 2 1 ∫ c o s x c o s 4 π + s i n x s i n 4 π d x
= 1 2 ∫ d x cos ( x − π 4 ) = \frac{1}{\sqrt{2}} \int \frac{dx}{\cos\left(x - \frac{\pi}{4}\right)} = 2 1 ∫ c o s ( x − 4 π ) d x
= 1 2 ∫ sec ( x − π 4 ) d x = \frac{1}{\sqrt{2}} \int \sec\left(x - \frac{\pi}{4}\right) dx = 2 1 ∫ sec ( x − 4 π ) d x
= 1 2 ln ∣ sec ( x − π 4 ) + tan ( x − π 4 ) ∣ + c = \frac{1}{\sqrt{2}} \ln \left| \sec\left(x - \frac{\pi}{4}\right) + \tan\left(x - \frac{\pi}{4}\right) \right| + c = 2 1 ln sec ( x − 4 π ) + tan ( x − 4 π ) + c
(যেখানে c c c একটি সমাকলন ধ্রুবক)
[অথবা: I = 1 2 ln ∣ tan ( x 2 + π 8 ) ∣ + c I = \frac{1}{\sqrt{2}} \ln\left|\tan\left(\frac{x}{2} + \frac{\pi}{8}\right)\right| + c I = 2 1 ln tan ( 2 x + 8 π ) + c ]